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Beats

Question

A sound source of frequency 170 Hz is placed near a wall. A man walking from a source towards the wall finds that there is a periodic rise and fall of sound intensity. If the speed of sound in air is 340 m/s the distance (in metres) separating the two adjacent positions of minimum intensity is

Moderate

A

1/2
B

1
C

3/2
D

2

Solution

$v = nλ \Rightarrow λ = \frac{v}{n} = \frac{340}{170} \Rightarrow λ = 2$
Distance separating the position of minimum intensity = $\frac{λ}{2} = \frac{2}{2} = 1 m$

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