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Doppler's effect

Question

A sound source is releasing a signal of constant frequency 330 Hz. f& λare frequency and wavelength observed by an observer. The velocity of sound in air is 330 ms1.

Column-IColumn-II
PThe observer & source move towards each other.1λ=1m,f>330Hz
Q

The observer and source are stationary, wind is

blowing towards source from observer.

2λ=1m,f=330Hz
R

The source is stationary, wind is blowing from source to 

observer and observer is moving away from the source.

3λ<1m,f>330Hz
S

The source is stationary and observer is moving 

towards source.

4λ=1m,f<330Hz

Moderate
Solution

λ=vf=330330=1m

P : As source and observer are moving towards each other f=f0u+u0u-us

Frequency increases and wavelength decreases.

Q : As source and observer are at rest vO=0 and vS=0 

wind is blowing from source to observer moving away from source= f=f0u+uw+u0u+uw-us=f0

Frequency remain same and wavelength also remain same.

R : Observer is moving towards stationary source=  f=f0u+uw-u0u+uw

Frequency decreases and wavelength remain same.

S :  f=f0u+u0u

Frequency increases and wavelength remain same.

 



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