Questions
A sound wave of frequency 440 Hz is passing through air. An molecule (mass = 5.3 × kg) is set in oscillation with an amplitude of m. Its speed at the centre of its oscillation is
detailed solution
Correct option is C
Vmax=ωnA = (2πf)A = (2π) 44010−6= 2.76 × 10−3m/sTalk to our academic expert!
Similar Questions
The identical springs of constant ‘K’ are connected in series and parallel as shown in figure A mass M is suspended from them. The ratio of their frequencies of vertical oscillations will be
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