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Q.

A sound wave of frequency 440 Hz is passing through air. An O2 molecule (mass = 5.3 x 10-26 kg) is set in oscillation with an amplitude of 10-8 m speed at the centre of its oscillation is:

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a

1.70×10-5 m/s

b

17.0×10-5 m/s

c

2.76 × 10-5 m/s

d

2.77 × 10-5 m/s

answer is C.

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Detailed Solution

vmax = ωnA         = (2πf)A = (2π)(440)(10-8)          = 2.76 × 10-5 m/s
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