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Q.

On sounding tuning fork A with another tuning fork B of frequency 384 Hz, 6 beats are produced per second. After loading the prongs of A with some wax and then sounding it again with B, 4 beats are produced per second. What is the frequency of the tuning fork A

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a

388 Hz

b

380 Hz

c

378 Hz

d

390 Hz

answer is D.

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Detailed Solution

nA = ?, nB = 384 Hz x = 6 bps, which is decreasing (from 6 to 4) i.e. x↓ Tuning fork A is loaded so nA↓Hence nA↓ – nB = x↓ → Correct nB – nA↓ = x↓ → Wrong⇒ nA = nB + x = 384 + 6 = 390 Hz.

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