On sounding tuning fork A with another tuning fork B of frequency 384 Hz, 6 beats are produced per second. After loading the prongs of A with some wax and then sounding it again with B, 4 beats are produced per second. What is the frequency of the tuning fork A
nA = ?, nB = 384 Hz
x = 6 bps, which is decreasing (from 6 to 4) i.e. x
Tuning fork A is loaded so nA
Hence nA – nB = x Correct
nB – nA = x Wrong
nA = nB + x = 384 + 6 = 390 Hz.