First slide

Doppler

Question

A source of frequency 512 c.p.s. moves towards a listener with a speed.of 100 m/sec. If the velocity of sound in ah is 350 m/sec, the frequency heard by
listener is

Moderate

A

7168sec^-1
B

7.168 sec ^-1
C

716 .8sec-¹
D

71.68 sec^-1

Solution

$n^{'} = (\frac{V}{V - V_{s}}) n ∴ n^{'} = (\frac{350}{350 - 100}) 512 = \frac{350 \times 512}{250} = 716 \cdot 8 Hz$

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