First slide

Photo Electric Effect

Question

A source of light is placed at a distance of 50 cm from a photo cell and the stopping potential is found to be $V_{0}$ . If the distance between the light source and photo cell is made 25 cm, the new stopping potential will be :

Easy

A

$V_{0} / 2$
B

$V_{0}$
C

$4 V_{0}$
D

$2 V_{0}$

Solution

By changing the position of source of light from photocell, there will be a change in the intensity of light falling on photocell.
As stopping potential is independent of the intensity of the incident light, hence stopping potential remains same
i.e., $V_{0}$ .

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