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Q.

A source of sound of frequency f1 is placed on the ground. A detector placed at a height is released from rest on this source. The observed frequency f(Hz) is plotted against time t(sec). The speed of sound in air is 300 m/s. Find f1g=10m/s2

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a

0.5×103Hz

b

1×103Hz

c

0.25×103

d

0.2×103Hz

answer is B.

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Detailed Solution

f=v+v0vf1=f1+f1v0vv0=gt So,  f=f1+f1gvt Slope of graph =f1gv=2×103−f130=f1(10)300 or f1=103Hz
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