First slide

Doppler's effect

Question

A source of sound of frequency 90 vibrations/ sec is approaching a stationary observer with a speed equal to 1/10 the speed of sound. What will be the frequency heard by the observer

Easy

A

80 vibrations/sec
B

90 vibrations/sec
C

100 vibrations/sec
D

120 vibrations/sec

Solution

$n' = n (\frac{v}{v - v_{s}}) = 90 (\frac{v}{v - \frac{v}{10}}) = 100 \frac{Vibration}{\sec}$

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