Doppler's effect

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Question

The source of sound generating a frequency of 3 kHz reaches an observer with a speed of 0.5 times speed of sound in air. The frequency(in kHz ) heard by the observer is

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Solution

According to Doppler's effect
$\begin{array}{l} f = (\frac{v \pm v_{0}}{v \pm v_{s}}) f \\ h e r e v_{0} = 0 a n d v_{s} = 0.5 v \\ ∴ f = (\frac{v}{v - 0.5 v}) 3 = 6 k H z \end{array}$

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