First slide

Doppler

Question

A source of sound produces waves of wavelength 60 cm when it is stationary. If the speed of sound in air is 320 $m s^{- 1}$ and source moves with speed 20 $m s^{- 1}$ , the wavelength of sound in the forward direction will be nearest to

Moderate

A

56 cm
B

60 cm
C

64 cm
D

68 cm

Solution

$\begin{array}{l} λ' = \frac{(c - v_{s}^{})}{f} = (\frac{c - v_{s}^{}}{c}) . λ \\ = (\frac{320 - 20}{320}) .60 c m = 56 c m . \end{array}$

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