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The source temperature of a heat engine is 1270C. It takes 500 Cal of heat from source and rejects 400Cal to the sink each cycle. The temperature of sink is 

a
320 K
b
47 K
c
101.60 C
d
101.6 K

detailed solution

Correct option is A

efficiency of heat engine =η=1-T2T1=1-Q2Q1T1,T2 are temperatures of source and sink;Q1,Q2 are heat absorbed and rejected respectively; from above equation,⇒Q2Q1=T2T1given Q1=500J ,Q2=400J;T1=127+273=400Kelvin,T2=? substitute in above equation,400500=T2127+273⇒T2=0.8×400=320K=temperature of sink

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