The space between the plates of a parallel plate capacitor is filled completely with a dielectric substance having dielectric constant 4 and thickness 3 mm and its capacitance is C. The distance between the plates in now increased by inserting a second sheet of thickness 5 mm and dielectric constant K. If the capacitance of the capacitor so formed is C/2 then the value of K is
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a
10/3
b
20/3
c
5/3
d
15/3
answer is B.
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Detailed Solution
Original capacitance 4CFinal capacitance4C×3KC54C+3KC5=4C2Solving K = 20/3