Questions
The space between the plates of a parallel plate capacitor is filled with a 'dielectric' whose 'dielectric constant' varies with distance as per the relation:
The capacitance C, of the capacitor, would be related to its vacuum capacitance by the relation:
detailed solution
Correct option is C
Capacitance of capacitor with dielectric material =C0=ε0AddC=ε0(K0+λx)Adx⇒1C=∫1dC⇒1C=∫0ddxε0(K0+λx)A⇒1C=1Aε0λ×[ln(K0+λx)]0d⇒1C=1Aε0λ×[ln(K0+λd)−ln(K0)]⇒C=Aε0λln(1+λdK0)⇒C=λdln(1+λdK0)C0Talk to our academic expert!
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There is an air filled 1 pF parallel plate capacitor. When the plate separation is doubled and the space is filled with wax, the capacitance increases to 2 pF. The dielectric constant of wax is
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