Questions
Span of a bridge is 2.4 km. At 30°C a cable along the span sags by 0.5 km. Taking a = 12 × /°C, change in length of cable for a change in temperature from 10°C to 42°C is
detailed solution
Correct option is C
Span of bridge = 2400 m and bridge sags by 500 m at 30° (given)From Fig., LPRQ = 212002+5002= 2600 mBut L = L0(1 +αΔt) Due to linear expansion ⇒ 2600 = L0l + 12 × 10−6× 30 Length of the cableL0=2599 m Now change in length of cable due to change in temperature from 10°C to 42°C ΔL= 2599 × 12 × 10−6× 42 − 10 = 0.99mTalk to our academic expert!
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