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Q.

The specific heat of water =4200  J  kg-1 K-1  and the latent heat of ice  =3.4×105  J  kg−1. 100 grams of ice at  0°C is placed in 200 g of water at  25°C. The amount of ice that will melt as the temperature of water reaches  0°C is close to (in grams) :

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a

61.7

b

64.6

c

63.8

d

69.3

answer is A.

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Detailed Solution

Heat extracted out of system  =0.2420025=21000 JSo amount of ice melt  =QL=210003.4×105  kg=2103.4 g=61.76  gm
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