Banner 0
Banner 1
Banner 2
Banner 3
Banner 4
Banner 5
Banner 6
Banner 7
Banner 8
Banner 9

Q.

The specific heat of water =4200  J  kg-1 K-1  and the latent heat of ice  =3.4×105  J  kg−1. 100 grams of ice at  0°C is placed in 200 g of water at  25°C. The amount of ice that will melt as the temperature of water reaches  0°C is close to (in grams) :

see full answer

Your Exam Success, Personally Taken Care Of

1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.
An Intiative by Sri Chaitanya

a

61.7

b

64.6

c

63.8

d

69.3

answer is A.

(Unlock A.I Detailed Solution for FREE)

Best Courses for You

JEE

JEE

NEET

NEET

Foundation JEE

Foundation JEE

Foundation NEET

Foundation NEET

CBSE

CBSE

Detailed Solution

Heat extracted out of system  =0.2420025=21000 JSo amount of ice melt  =QL=210003.4×105  kg=2103.4 g=61.76  gm
Watch 3-min video & get full concept clarity
score_test_img

courses

No courses found

Get Expert Academic Guidance – Connect with a Counselor Today!

whats app icon
personalised 1:1 online tutoring
The specific heat of water =4200  J  kg-1 K-1  and the latent heat of ice  =3.4×105  J  kg−1. 100 grams of ice at  0°C is placed in 200 g of water at  25°C. The amount of ice that will melt as the temperature of water reaches  0°C is close to (in grams) :