The specific heat of water =4200 J kg-1 K-1 and the latent heat of ice =3.4×105 J kg−1. 100 grams of ice at 0°C is placed in 200 g of water at 25°C. The amount of ice that will melt as the temperature of water reaches 0°C is close to (in grams) :

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61.7

64.6

63.8

69.3

answer is A.

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Detailed Solution

Heat extracted out of system =0.2420025=21000 JSo amount of ice melt =QL=210003.4×105 kg=2103.4 g=61.76 gm

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