Questions
The specific resistance of a thin wire of radius resistance and length Find the percentage error in is
a
18%
b
20%
c
16%
d
22%
detailed solution
Correct option is A
Specific Resistance ρ=πr2Rl differentiate and divide with the same equation then multiply by 100 both sides Δ ρρ×100=2Δ rr×100+Δ RR×100+Δ ll×100 Δ ρρ×100=[2×0.020.26+132+0.0178]×100 Δ ρρ×100=0.1538+0.03125+0.000128×100 percentage error in ρ=0.185 ×100=18%Talk to our academic expert!
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