First slide

Polarisation

Question

Specific rotation of sugar solution is 0.01 SI units. $200 {kgm}^{- 3}$ of impure sugar solution is taken in a polarimeter tube of length 0.25 m and an optical rotation of 0.4 rad is observed. The percentage of purity of sugar is the sample is

Easy

A

80%
B

89%
C

11%
D

20%

Solution

Specific rotation
$(α) = \frac{θ}{lc} \Rightarrow c = \frac{θ}{αl} = \frac{0 .4}{0 .01 \times 0 .25} = 160 kg / m^{3}$
Now percentage purity of sugar solution
$= \frac{160}{200} \times 100 = 80 %$

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