First slide

Relative velocity in 1-d

Question

The speed of a motor launch with respect to the water is v = 5 ms^-1, the speed of stream u= 3 ms^-1. When the launch began travelled 3.6 km up stream, turned about and caught up with the float. How long is it before the launch reaches the float again? (Find answer in hour).

Moderate

Solution

$\begin{array}{l} t = \frac{2 t}{v - u} = \frac{2 \times 3600}{2} \\ \Rightarrow t = 3600 s \\ \Rightarrow t = 1 h \end{array}$

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