Q.
The speed of a particle executing SHM is given by the equation v2=144−9x2 then the wrong statements among the following is
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a
Amplitude of the particle is 4 units
b
Time period is π3 units
c
Maximum velocity is 12 units
d
Maximum acceleration is 36 units
answer is B.
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Detailed Solution
maximum velocity in SHM is at x = 0 that is when there is no displacement. Thus putting x = 0, the maximum velocity comes out to be = 12 units V=144−9x2=342−x2 Comparing with the equation V=ωA2−x2 we get ω=3 and A=4As a result T = 2π/3 Also we know acceleration = −ω2x in the case of SHMFor maximum acceleration x=A=4 which gives us maximum acceleration as 36 units, Hence option 3 is wrong.
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