The speed of a particle executing SHM is given by the equation v2=144−9x2 then the wrong statements among the following is
see full answer
Your Exam Success, Personally Taken Care Of
1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.
An Intiative by Sri Chaitanya
a
Amplitude of the particle is 4 units
b
Time period is π3 units
c
Maximum velocity is 12 units
d
Maximum acceleration is 36 units
answer is B.
(Unlock A.I Detailed Solution for FREE)
Best Courses for You
JEE
NEET
Foundation JEE
Foundation NEET
CBSE
Detailed Solution
maximum velocity in SHM is at x = 0 that is when there is no displacement. Thus putting x = 0, the maximum velocity comes out to be = 12 units V=144−9x2=342−x2 Comparing with the equation V=ωA2−x2 we get ω=3 and A=4As a result T = 2π/3 Also we know acceleration = −ω2x in the case of SHMFor maximum acceleration x=A=4 which gives us maximum acceleration as 36 units, Hence option 3 is wrong.