The speed of a projectile at its maximum height is √3/2 times its initial speed. If the range of the projectile is p times the maximum height attained by it, then p =
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a
4/3
b
2√3
c
4√3
d
3/4
answer is C.
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Detailed Solution
Given R = PH............ (1)from equation (1) & (2), we have P = 4√3