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Q.

The speed of a projectile at its maximum height is √3/2 times its initial speed. If the range of the projectile is p times the maximum height attained by it, then p =

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a

4/3

b

2√3

c

4√3

d

3/4

answer is C.

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Detailed Solution

Given R = PH............ (1)from equation (1) & (2), we have P = 4√3
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