The speed of a projectile at its maximum height is 32 times its initial speed.  If the range of the projectile is n times the maximum height attainted by it, n is equal to:

Given 3u2=ucosθ= speed at maximum height cosθ=32  or θ=300                -------- (i)Given that nHmax=R                    ---------- (ii)We know Hmax=Rtanθ4 n=4tanθ=4tan300=43 .