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Questions  

 The speed of a projectile at its maximum height is  3/2 times its initial speed. If the range of the projectile is P times the maximum height attained by it, P is equal to

a
4/3
b
23
c
43
d
3/4

detailed solution

Correct option is C

Given 3u2=ucosθ= speed at maximum height  cosθ=32   or   θ=30°  Given matPHmax=R  We know Hmax=Rtanθ4 P=RHmax=4tanθ=4tan30°=43

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Similar Questions

Assertion : When the velocity of projection of a body is made n times, its time of flight becomes n times.

Reason : Range of projectile does not depend on the initial velocity of a body.


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