The speed of a projectile at its maximum height is 32 times its initial speed. If the range of the projectile is n times the maximum height attained by it, n is equal to:

Given 32u = u cos θ = speed at maximum heightcos θ = 32or θ = 300------------------------(i)Given that nHmax. = R-----(ii)We know Hmax. = R tan θ4n =4tan θ  = 4 tan 300 = 43