The speed of a projectile at its maximum height is 32 times its initial speed. If the range of the projectile is 'P' times the maximum height attained by it. P is-
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a
43
b
23
c
43
d
34
answer is C.
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Detailed Solution
Given, ucosθ=3u2⇒cosθ=32⇒θ=30° Range (R)=u2sin2θg=u2sin60°g=3u22g Maximum height =u2sin2θ2g=u2sin230°2g=u28g Now, Range =P×H⇒3u22g=P×u28g⇒P=43