The speed of a projectile at its maximum height is 3/2times its initial speed. If the range of the projectile is P times the maximum height attained by it, P is equal to
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a
4/3
b
23
c
43
d
3/4
answer is C.
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Detailed Solution
Given 3u2=ucosθ= speed at maximum height or cosθ=32 or θ=30∘ .......(i) Given that PHmax=R ......(ii) We know Hmax=Rtanθ4P=RHmax=4tanθ=4tan30∘=43
The speed of a projectile at its maximum height is 3/2times its initial speed. If the range of the projectile is P times the maximum height attained by it, P is equal to