The speed of a projectile at its maximum height is 32times its initial speed. If the range of the projectile is P times the maximum height attained by it, P is equal to
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a
4/3
b
23
c
43
d
¾
answer is C.
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Detailed Solution
Given 3u2=ucosθ = speed at maximum height or cosθ=32 or θ = 30o ......(i)Given mat PHmax = R ........(ii)We know Hmax=Rtanθ4P=RHmax=4tanθ=4tan30o=43