The speed v of a particle moving along a straight line when it is at a distance x from a fixed point on the line is given by v2=144−9x2. Select the correct alternatives
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a
The motion of the particle is SHM with time period T=2π3unit
b
The maximum displacement of the particle from the fixed point is 8 unit
c
The magnitude of the acceleration at a distance 3 unit from the fixed point is 24 unit
d
The motion of the particle is periodic but not simple harmonic
answer is A.
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Detailed Solution
The equation resembles equation for velocity of SHM.v=ωA2-x2Comparing given equation v2=144−9x2. with equation of SHM, v2=A2ω2−x2ω2 we get, ω=3, A=4 .T=2πω=2π3 unitMaximum displacement = A = 4 unit. Hence option (B) is wronga=ω2x=9(3)=27 unit. Hence option (C) is wrongDifferentiating v2=144−9x2, we get a α−x . This makes it simple harmonic motion. Hence option (D) is wrong.
The speed v of a particle moving along a straight line when it is at a distance x from a fixed point on the line is given by v2=144−9x2. Select the correct alternatives