The speed v reached by a car of mass m in travelling a distance x, driven with constant power P, is given by
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a
v=3xPm
b
v=3xPm12
c
v=3xPm13
d
v=3xPm2
answer is C.
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Detailed Solution
powere =P= Fv here F is force, v is velocity, and F= ma, here a is accelerationP =m dvdt v, here differential form of acceleration is consideredor v dvdt= Pmor v dvdxdxdt=Pm , here in left hand side , divide and multiply by dx,or v2dvdx=Pm or v2dv=Pmdx ∫v2dv=∫PmdxOn integration , we get v33=Pxm or v = 3xPm13