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Q.

Speeds of air blow on the upper and lower surfaces of a wing of an aeroplane are V1  and V2 respectively.  If A be the cross sectional area of the wing and ρ be the density of air, then the upward lift is

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a

12 ρAV1  − V2

b

14 ρAV12  − V22

c

12 ρAV12  − V22

d

14 ρAV12  + V22

answer is C.

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Detailed Solution

(3) Applying Bernoulli's equation between points (1) and (2),P1+12 ρV12=P2+12 ρV22⇒  P2−P1=12PV12  − V22∴   Upward  lift  =  P2−P1A  = 12 ρA V12  − V22
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