A sphere of 4cm radius is suspended in a hollow sphere of 6cm radius. The inner sphere is charged to potential 3 e.s.u. and the outer sphere is earthed. The charge on the inner sphere is
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a
54 e.s.u.
b
14e.s.u.
c
30 e.s.u.
d
36 e.s.u.
answer is D.
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Detailed Solution
Suppose charge on inner sphere is +Q as shown.Potential on inner sphereV=V1+V2=kQ1r1+kQ2r2=1Q4+1-Q6 ∵k =1, Q1=Q, Q2=-Q ⇒3=Q14−16 ⇒Q=36 e.s.u.