A sphere of mass m, moving with velocity V, enters a hanging bag of sand and stops. If the mass of the bag is M and it is raised by height h, then the velocity of the sphere was
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a
M+mm2gh
b
Mm2gh
c
mM+m2gh
d
mM2gh
answer is A.
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Detailed Solution
By the conservation of linear momentum Initial momentum of sphere = Final momentum of system mV=(m+M)vsys. …(i) If the system rises up to height h then by the conservation of energy 12(m+M)vsys.2=(m+M)gh …(ii)⇒vsys.=2ghSubstituting this value in equation (i) V=m+Mm 2gh