First slide
Rolling motion
Question

A sphere of outer radius R having some cavity inside is allowed to roll down on an incline without slipping and it reaches a speed v0 at the bottom of the incline. The incline is then made smooth by waxing and the sphere is allowed to slide without rolling and now the speed attained is (54)v0. What is the radius of gyration of the sphere about an axis passing through its centre?

Difficult
Solution

 

Applying law of CONSERVATION OF ENERGY in the case of rolling

12mvo2+12I(voR)2 = mgh

Applying law of CONSERVATION OF ENERGY in the case of sliding

12m(54vo)2 = mgh

solve them to get: I = 916mR2

now I = mK2, K = Im = 34R

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