The sphere at P is given a downward velocity v0and swings in a vertical plane at the end of a rope of length l=1mattached to a support at O. The rope breaks at angle 300from horizontal, knowing that it can withstand a maximum tension equal to three times the weight of the sphere. Then the value of v0 will be :

see full answer

Talk to JEE/NEET 2025 Toppers - Learn What Actually Works!

Real Strategies. Real People. Real Success Stories - Just 1 call away

An Intiative by Sri Chaitanya

g2ms-1

2g3ms-1

3g2 ms-1

g3ms-1

answer is C.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

when it travels 300 from the initial position the loss in potential energy is mgl sin300= mg/2 l=1mtension in the string in the displaced positionT= mv2l+mg cos600=3mg mv2=3mg-mgcos600= 5mg2 (12mv2=5mg4applying conservation of energy 12mv02 +mgl2= 12mv2=5mg4mv02=5mg2-mg=3mg2 v0=3g2

Watch 3-min video & get full concept clarity

Result Producing online coaching for JEE/NEET of south India

Largest All India Test Series for JEE/NEET

Best Online Course for IIT JEE

Best Online Course for NEET

Best Online Course for CBSE

Get Expert Academic Guidance – Connect with a Counselor Today!

Result Producing online coaching for JEE/NEET of south India

Largest All India Test Series for JEE/NEET

Best Online Course for IIT JEE

Best Online Course for NEET

Best Online Course for CBSE