Questions
A sphere pure rolls on a rough inclined plane with initial velocity 2.8 ms-1 . Find the maximum distance on the inclined plane.
detailed solution
Correct option is C
Given, initial velocity of sphere, u=2.8ms−1Acceleration on the inclined plane,a=gsinθ1+K2R2 …(i)where, K and R are the radius of gyration and radius of sphere, respectively.Moment of inertia of sphere I=mK2=25mR2For sphere, K2R2=25Putting this value in Eq. 0), we geta=gsin30∘1+25 ∵θ=30∘( given ) =5g14=257ms−2 ∵g=10ms−2If s be the maximum distance travelled by the sphere, then at maximum distance, v =0.∴ From third equation of motion, v2=u2−2as0=u2−2as⇒ s=u22a=(2.8)2×72×25=1.09m≃1.38mTalk to our academic expert!
Similar Questions
A solid cylinder of mass 2 kg and radius 50 cm rolls up an inclined plane of angle inclination 300. The centre of mass of cylinder has speed of 4 ms-1. The distance travelled by the cylinder on the inclined surface will be
(Take, g = 10 ms-2
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