First slide

Electrostatic potential energy

Question

A sphere of radius 1 cm has potential of 8000 V, then energy density near its surface will be

Easy

A

$64 \times 10^{5} J / m^{3}$
B

$8 \times 10^{3} J / m^{3}$
C

$32 J / m^{3}$
D

$2 .83 J / m^{3}$

Solution

Energy density $u_{e} = \frac{1}{2} ε_{0} E^{2} = \frac{1}{2} \times 8 .86 \times 10^{- 12} \times {(\frac{V}{r})}^{2} = 2 .83 J / m^{3}$

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