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Questions  

A sphere of radius 1 cm has potential of 8000 V, then energy density near its surface will be 

a
64×105J/m3
b
8×103J/m3
c
32 J/m3
d
2.83 J/m3

detailed solution

Correct option is D

Energy density ue=12ε0E2=12×8.86×10−12×Vr2= 2.83J/m3

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