First slide

Potential energy

Question

A sphere of radius 1 cm has potential of 8000 V, then energy density near its surface will be

Easy

A

64 x 10⁵ J/m³
B

8 x 10³ J/m³
C

32 J/m³
D

2.83 J/m³

Solution

$Energy density u_{e} = \frac{1}{2} ε_{0} E^{2} = \frac{1}{2} \times 8.86 \times 10^{- 12} \times {(\frac{V}{r})}^{2} = 2.83 J / m^{3}$

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