Banner 0
Banner 1
Banner 2
Banner 3
Banner 4
Banner 5
Banner 6
Banner 7
Banner 8
Banner 9

Q.

sphere S of mass M is given a finite angular velocity about a horizontal axis through its centre. Now it is gently placed on a plank p of the same mass. The coefficient of friction between the two is μ and the plank rests on a smooth horizontal surface as shown in fig. (6). The initial acceleration of the sphere relative tothe plank will be

see full answer

High-Paying Jobs That Even AI Can’t Replace — Through JEE/NEET

🎯 Hear from the experts why preparing for JEE/NEET today sets you up for future-proof, high-income careers tomorrow.
An Intiative by Sri Chaitanya

a

μg

b

2/5 .μg

c

2μg

d

zero

answer is C.

(Unlock A.I Detailed Solution for FREE)

Best Courses for You

JEE

JEE

NEET

NEET

Foundation JEE

Foundation JEE

Foundation NEET

Foundation NEET

CBSE

CBSE

Detailed Solution

The horizontal force acting between the two bodies is the frictional force (μ mg) So, the acceleration of each body will be μ Mg /M=μ g  in opposite direction' Therefore,relative acceleration=2 μ g
Watch 3-min video & get full concept clarity

courses

No courses found

score_test_img

Get Expert Academic Guidance – Connect with a Counselor Today!

whats app icon
sphere S of mass M is given a finite angular velocity about a horizontal axis through its centre. Now it is gently placed on a plank p of the same mass. The coefficient of friction between the two is μ and the plank rests on a smooth horizontal surface as shown in fig. (6). The initial acceleration of the sphere relative tothe plank will be