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Q.

A spherical ball A of mass 4 kg, moving along a straight line strikes another spherical ball B of mass 1 kg at rest. After the collision, A and B move with velocities v1 ms-1  and v2 ms-1 respectively making angles of 300 and 600 with respect to the original direction of motion of A. The ratio v1v2 will be

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a

3/4

b

4/3

c

1/3

d

3

answer is A.

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Detailed Solution

Apply the law of conservation of linear momentum along a direction perpendicular to the direction of motion (i.e. along y-axis), we get0+0=4v1sin30°−v2sin60°​⇒4v1sin30°=v2sin60°​⇒v1v2=sin60°4sin30°=34
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A spherical ball A of mass 4 kg, moving along a straight line strikes another spherical ball B of mass 1 kg at rest. After the collision, A and B move with velocities v1 ms-1  and v2 ms-1 respectively making angles of 300 and 600 with respect to the original direction of motion of A. The ratio v1v2 will be