First slide
Dynamics of rotational motion about fixed axis
Question

A spherical ball of mass 20 kg is stationary at the top of a hill of height 100 m. It rolls down a smooth surface to the ground, then climbs up another hill of height 30 m and finally rolls down to a horizontal base at a height of 20 m above the ground. The velocity attained by the ball is :

Easy
Solution

As ball rolls down on smooth surface 
So, v=2gh=2×10×(10020)=1600=40m/s

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