First slide

Types of charge distribution

Question

A spherical charged conductor has $σ$ as the surface density of charge. The electric field on its surface is ‘E’. If the radius of the sphere is doubled, keeping surface density of charge unchanged, What will be the electric field on the surface of the new spheres?

Moderate

A

E/4
B

E/2
C

E
D

E/3

Solution

$\begin{array}{l} E = K . \frac{4 {πR}^{2} . σ}{R^{2}} = 4 πkσ \\ E' = k . \frac{4 π {(2 R)}^{2} . σ}{4 R^{2}} = E \end{array}$

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