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A spherical object cools from $80^{0} C t o 64^{0} C i n 5 \min .$ The same body cools from $80^{0} C t o 52^{0} C i n 10 \min .$ Then temperature of the surrounding is

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Correct option is B

(2)According to Newton's Law of cooling,80−645 = K80+642−θ0 .....180−5210 = K80+522−θ0 .....21 ÷ 2 ⇒ 3.22.8 = 72− θ066−θ0 ⇒ θ0=240C

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A spherical object cools from 800C to 640C in 5 min. The same body cools from 800C to 520C in 10 min. Then temperature of the surrounding is

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A spherical object cools from $80^{0} C t o 64^{0} C i n 5 \min .$ The same body cools from $80^{0} C t o 52^{0} C i n 10 \min .$ Then temperature of the surrounding is