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Q.

A spherical object cools from 800C  to 640C  in  5 min. The same body cools from 800C  to 520C  in  10 min. Then temperature of the surrounding is

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a

180C

b

240C

c

220C

d

160C

answer is B.

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Detailed Solution

(2)According to Newton's Law of cooling,80−645 =  K80+642−θ0    .....180−5210 =  K80+522−θ0    .....21  ÷  2 ⇒  3.22.8  =  72− θ066−θ0  ⇒  θ0=240C
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