First slide
Release from certain height
Question

A splash is heard 3.12s after a stone is dropped into a well 45 m deep. The speed of sound in air is [g = 10 ms-2]

Easy
Solution

\large time\;of\;fall = \sqrt {\frac{{2h}} {g}} \Rightarrow t = \sqrt {\frac{{2 \times 45}} {{10}}} = 3

remaining time = 3.12 - 3 = 0.12 sec

speed = 45 /0.12 = 375 ms-1

 

Get Instant Solutions
When in doubt download our app. Now available Google Play Store- Doubts App
Download Now
Doubts App