A spool is rolling without slipping on a strip with velocity v as shown in figure. Then acceleration of point A relative to ground is
5v2R
v22R
3v2R
5v22R
Length AO=R2 2R2 = 5 R
∴ Velocity of A relative to ground
= Velocity of A relative to O = ω OA = vR 5R
=5 V
Now acceleration of centre C, aC = 0
Also, a→A = a→C + a→A/C = a→A/C ⇒ aA=aA/C = vA2CA = 5v22R = 5V22R