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A spool is rolling without slipping on a strip with velocity v as shown in figure. Then acceleration of point A relative to ground is

a
5v2R
b
v22R
c
3v2R
d
5v22R

detailed solution

Correct option is D

Length AO=R2 2R2 =  5 R∴   Velocity of A relative to ground= Velocity of A relative to O = ω OA =  vR 5R=5 VNow acceleration of centre C, aC = 0Also,  a→A  =  a→C +  a→A/C  =  a→A/C  ⇒   aA=aA/C = vA2CA  =  5v22R =  5V22R

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