First slide

Pseudo force

Question

A spring balance is attached to the ceiling of a lift. A man hangs his bag on the spring and the spring reads 49 N, when the lift is stationary. If the lift moves downward with an acceleration of 5 m/s², the reading of the spring balance will be :

Easy

A

24 N
B

74N
C

15N
D

49N

Solution

According to question, mg = 49 (lift is stationary)
If lift is moving then reading
$= m (g - a) = m (g - \frac{g}{2}) = \frac{mg}{2} = \frac{49}{2} ≃ 24 N$

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