A spring balance is attached to the ceiling of a lift. A man hangs his bag on the spring and the spring reads 49 N, when the lift is stationary. If the lift moves downward with an acceleration of 5 m/s2,the reading of the spring balance will be
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a
49 N
b
24 N
c
74 N
d
15 N
answer is B.
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Detailed Solution
When the lift is stationary W=mg⇒49=m×9.8⇒m=5kg.When the lift is moving downward with an acceleration R=m(9.8−a)=5[9.8−5]=24N