A spring balance is attached to the ceiling of a lift. A man hangs his bag on the spring and the spring reads 49 N, when the lift is stationary. If the lift moves downward with an acceleration of 5 m/s2,the reading of the spring balance will be

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49 N

24 N

74 N

15 N

answer is B.

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Detailed Solution

When the lift is stationary W=mg⇒49=m×9.8⇒m=5kg.When the lift is moving downward with an acceleration R=m(9.8−a)=5[9.8−5]=24N

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