First slide

Applications of SHM

Question

A spring executes SHM with mass of 10kg attached to it. The force constant of spring is 10N/m.If at any instant its velocity is 40cm/sec, the displacement will be (where amplitude is 0.5m)

Moderate

A

0.09 m
B

0.3 m
C

0.03 m
D

0.9 m

Solution

Angular velocity $ω = \sqrt{(\frac{k}{m})} = \sqrt{(\frac{10}{10})} = 1$
Now $u = ω \sqrt{a^{2} - y^{2}} \Rightarrow y^{2} = a^{2} - \frac{v^{2}}{ω^{2}} = {(0 .5)}^{2} - \frac{{(0 .4)}^{2}}{1^{2}}$
$\Rightarrow y^{2} = 0 .9 \Rightarrow y = 0 .3 m$

Get Instant Solutions

When in doubt download our app. Now available Google Play Store- Doubts App

Recieve an sms with download link

Doubts App

OR

SCAN ME

Doubts App

Doubts App