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Q.

A spring executes SHM with mass of 10kg attached to it. The force constant of spring is 10N/m.If at any instant its velocity is 40cm/sec, the displacement will be (where amplitude is 0.5m)

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a

0.09 m

b

0.3 m

c

0.03 m

d

0.9 m

answer is B.

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Detailed Solution

Angular velocity  ω=km=1010=1Now u=ωa2−y2⇒y2=a2−v2ω2=(0.5)2−(0.4)212⇒y2=0.9⇒y=0.3 m
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