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Questions  

The spring extends by x on loading, then energy stored by the spring is If (If T is the tension in spring and ft is spring constant)

a
T2/2k
b
T2/2k2
c
2k/T2
d
2T2/k

detailed solution

Correct option is A

Energy stored in the spring,U=12kx2 where k is spring constant According to Hooke's law, T=k× ∴ x=(T/k) From eqs. (1) and (2), we 8et U=12T2k

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Similar Questions

Two similar springs P and Q have spring constants Kp and KQ such that Kp > KQ. They are stretched first by the same amount (case a), then by the same force (case b). The work done by the springs WP and WQ are related as, in case (a) and case (b), respectively.


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