First slide

Simple hormonic motion

Question

A spring of force constant fr is cut into lengths of ratio 1: 2: 3. They are connected in series and the new force constant is k'. Then they are connected in parallel and force constant is k" . Then k' : k" is :

Moderate

A

1 : 9
B

1 :11
C

1 :14
D

1 :16

Solution

Length of the spring segments $= \frac{l}{6}, \frac{l}{3}, \frac{l}{2}$
As we know $k \propto \frac{1}{l}$
So, spring constant for spring segments will be
$k_{1} = 6 k, k_{2} = 3 k, k_{3} = 2 k$
So in parallel combination
$k " = k_{1} + k_{2} + k_{3} = 11 k$
In series combination
$k' = k$ (As it will become original spring)
So, $k' : k " = 1 : 11$

Get Instant Solutions

When in doubt download our app. Now available Google Play Store- Doubts App

Recieve an sms with download link

Doubts App

OR

SCAN ME

Doubts App

Doubts App