A spring of force constant fr is cut into lengths of ratio $$1$$: $$2$$: $$3$$. They are connected in series and the new force constant is k'. Then they are connected in parallel and force constant is k" . Then k' : k" is :

Question

Infinity Learn · Accepted Answer

Length of the spring segments $$=l6$$,$$l3$$,$$l2As$$ we know k∝$$1lSo$$, spring constant for spring segments will be            $$k1=6k$$,$$k2=3k$$,$$k3=2kSo$$ in parallel combination        k"$$=k1+k2+k3=11$$ kIn series combination       k'$$=k$$ $$(As$$ it will become original $$spring)So$$,  k':k"$$=1$$ : $$11$$

A spring of force constant fr is cut into lengths of ratio 1: 2: 3. They are connected in series and the new force constant is k'. Then they are connected in parallel and force constant is k" . Then k' : k" is :

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