First slide

Applications of SHM

Question

A spring of force constant k is cut into two pieces such that one piece is double the length of the other. Then the long piece will have a force constant of

Moderate

A

$(2 / 3) k$
B

$(3 / 2) k$
C

$3 k$
D

$6 k$

Solution

Force constant $(k) \propto \frac{1}{Length of spring}$
$\Rightarrow \frac{K}{K_{1}} = \frac{l_{1}}{l} = \frac{\frac{2}{3} l}{l} \Rightarrow K_{1} = \frac{3}{2} K$ .

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